Equilibria chemistry - Gaseous equilibria - Checking Understanding

What is the equation linking K_c and K_p for the equilibrium system:

2SO₂(g) + O₂(g) _∏ 2SO₃(g)?

A

The equation is K_c = K_p.

B

The equation is K_c = K_p(RT).

C

The equation is K_c = K_p(RT)^–1.

D

The answer is K_c = K_p(RT)^–2.

What is the expression for K_p for the equilibrium system:

CaCO₃(s) _∏ CaO(s) + CO₂(g)?

A

$\inline \dpi{100} K_{\textup{p}}= \frac{(P_{\textup{CaO}})(P_{\textup{CO}_{_{2}}})}{(P_{\textup{CaCO}_{3}})}$

B

$\inline \dpi{100} K_{\textup{p}}= \frac{(P_{_{\textup{CaCO}_{3}}})}{(P_{\textup{CaO}})(P_{\textup{CO}_{2}})}$

C

$\inline \dpi{100} K_{\textup{p}}= (P_{\textup{CO}_{2}})^{-1}$

D

$\inline \dpi{100} K_{\textup{p}}= (P_{\textup{CO}_{2}})$

What are the units of K_p for the equilibrium system:

CH₄(g) + 2H₂(g) _∏ CH₃OH(g)

where partial pressures are measured in Pa?

A

The units of K_p are Pa.

B

The units of K_p are Pa².

C

The units of K_p are Pa^–2.

D

The units of K_p are Pa^–3.

What is the K_p expression for the equilbrium system:

CH₄(g) + 2H₂(g) _∏ CH₃OH(g)?

A

The expression is $\inline \dpi{100} K_{\textup{p}}= \frac{(P_{\textup{CH}_{4}})(P_{\textup{H}_{2}})^{2}}{(P_{\textup{CH}_{3}\textup{OH}})}$

B

The expression is $\inline \dpi{100} K_{\textup{p}}= \frac{(P_{\textup{CH}_{_{3}}\textup{OH}})}{(P_{\textup{CH}_{4}})(P_{\textup{H}_{2}})}$

C

The expression is $\inline \dpi{100} K_{\textup{p}}= \frac{(P_{\textup{CH}_{3}\textup{OH}})}{(P_{\textup{CH}_{4}})(P_{\textup{H}_{2}})^{2}}$

D

The expression is $\inline \dpi{100} K_{\textup{p}}= \frac{[\textup{CH}_{3}\textup{OH}]}{[\textup{CH}_{4}][\textup{H}_{2}]^{2}}$

An equilibrium mixture is made up of gases A, B and C in the ratio 1:2:3 moles at a total pressure of 300 atmospheres. What is the partial pressure of gas B?

A

1/2 x 300 = 150 atmospheres.

B

2/6 x 300 = 100 atmospheres.

C

2/4 x 300 = 150 atmospheres.

D

1/6 x 300 = 50 atmospheres.

Gaseous equilibria

Self assessment